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4=252/d^2
We move all terms to the left:
4-(252/d^2)=0
Domain of the equation: d^2)!=0We get rid of parentheses
d!=0/1
d!=0
d∈R
-252/d^2+4=0
We multiply all the terms by the denominator
4*d^2-252=0
We add all the numbers together, and all the variables
4d^2-252=0
a = 4; b = 0; c = -252;
Δ = b2-4ac
Δ = 02-4·4·(-252)
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{7}}{2*4}=\frac{0-24\sqrt{7}}{8} =-\frac{24\sqrt{7}}{8} =-3\sqrt{7} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{7}}{2*4}=\frac{0+24\sqrt{7}}{8} =\frac{24\sqrt{7}}{8} =3\sqrt{7} $
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